Where is ambient air connector in 2012 Cross Roads?
Is ambient air "sensor" 30KΩ ptc/ntc resistor or what?
I`m not ready to pay 60€ to my dealer for "original" status.
In side the faring. The only way it works I believe is to have your gages unlocked
Its on the left side and it looks like a bare electrical connector
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The Cross Roads needs the Ambient Temp unlocked in the speedometer as it normally is not an enabled feature of the stock Cross Roads. The temp sensor is not installed on the Cross Roads which is why you need one lol. As for the actual resistor value, I am not much help but just wanted to clear up what seemed like confusion on the Cross Roads.
The Cross Roads needs the Ambient Temp unlocked in the speedometer as it normally is not an enabled feature of the stock Cross Roads.
Actually just connecting the sensor enables it. The dealer thought this was the extent of the speedo reflash as the ambient temp suddenly showed up on the panel and never actually performed the upgrade. I've since explained to him that there was more than that.
Unfortunately my multimeter is at work, so I can measure it. I'll try and measure it next week when I return. I imagine I'm just looking for the resistance drop across the leads on the connector?
Where is ambient air connector in 2012 Cross Roads?
Is ambient air "sensor" 30KΩ ptc/ntc resistor or what?
I`m not ready to pay 60€ to my dealer for "original" status.
I checked the service manual and the only "ambient air" sensor that I can find is in Chapter 5, Fuel System/Fuel Injection. It is located on the rear cylinder, intake port in TMAP sensor. (pg 5.42) I don't think that is the one you are looking for.
Looks to be (according to pg. 19.6 in service manual) that the ambient air signal goes to the speedometer via pin 14 on the speedometer plug. Perhaps that will lead you to a connector looking for an input. Please let us know your findings.
Ok, after little work i found that connector.
It is inside headlight and wires are orange/blue and brown/blue.
Wires go to speedo pins 7 and 14.
I try with potentiometer and
0 degrees is 29,85Kohm
10 degrees is 19,8 Kohm
20 degrees is 12,3 Kohm
Now little calculations and so.......